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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)

Only litre buffer solution was prepared by adding 0.10 mol each of \(\mathrm{NH}_3\) and \(\mathrm{NH}_4 \mathrm{Cl}\) in deionised water. The change in pH on addition of 0.05 mol of HCl to the above solution is ________ \(\times 10^{-2}\), (Nearest integer) (Given : \(\mathrm{pK}_{\mathrm{b}}\) of \(\mathrm{NH}_3=4.745\) and \(\log _{10} 3=0.477\))

  1. A 40
  2. B 48
  3. C 50
  4. D 52
Verified Solution

Answer & Solution

Correct Answer

(B) 48

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \mathrm{pOH}=\mathrm{pK}_{\mathrm{b}}+\log \frac{\left[\mathrm{NH}_4^{+}\right]}{\left[\mathrm{NH}_3\right]} \\ & \mathbf{p O H}=4.745 \end{aligned}\) on adding 0.05 mole HCl…
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