JEE Mains · Chemistry · STD 12 - p -Block elements - ll
One mole of \(P _4\) reacts with \(8\) moles of \(SOCl _2\) to give \(4\) moles of \(A , x\) mole of \(SO _2\) and \(2\) moles of B. A, B and \(x\) respectively are
- A \(PCl _3, S _2 Cl _2\) and \(4\)
- B \(POCl _3, S _2 Cl _2\) and \(4\)
- C \(PCl _3, S _2 Cl _2\) and \(2\)
- D \(POCl _3, S _2 Cl _2\) and \(2\)
Answer & Solution
Correct Answer
(A) \(PCl _3, S _2 Cl _2\) and \(4\)
Step-by-step Solution
Detailed explanation
\(P _4+8 SOCl _2 \rightarrow 4 PCl _5+2 S _2 Cl _2+4 SO _2\)
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