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JEE Mains · Chemistry · STD 11 - 2. structure of atom
Given \((A)\, n = 5, m_l= + 1\)
\((B)\, n =2, l =1, m_l= -1, m_s = -1/2\)
The maximum number of electron\((s)\) in an atom that can have the quantum numbers as given in \((A)\) and \((B)\) are respectively
- A \(25\) and \(1\)
- B \(8\) and \(1\)
- C \(2\) and \(4\)
- D \(4\) and \(1\)
Answer & Solution
Correct Answer
(B) \(8\) and \(1\)
Step-by-step Solution
Detailed explanation
\((i)\) \(n=5\) means \(l=0,1,2,3,4\) since \(m= +1\) hence total no. of electrons will be \(= 0\) (from \(s\)) \(+ 2\) (from \(p\)) \(+ 2\) (fron \(d\)) \(+ 2\) (from \(f\)) \(+ 2\) (from \(g\)) \(=0+2+2+2+2=8\) \((ii)\) \(n=2,\,l=1,\,m_l=-1,\,m_s=-1/2\) represent \(2p\)…
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