ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 11. thermodynamics

An electric appliance supplies \(6000\, {J} / {min}\) heat to the system. If the system delivers a power of \(90\, {W}\). How long (in \(sec\)) it would take to increase the internal energy by \(2.5 \times 10^{3}\, {J}\) ?

  1. A \(250\)
  2. B \(410\)
  3. C \(300\)
  4. D \(150\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(250\)

Step-by-step Solution

Detailed explanation

\(\Delta \mathrm{Q}=\Delta \mathrm{U}+\Delta \mathrm{W}\) \(\frac{\Delta \mathrm{Q}}{\Delta \mathrm{t}}=\frac{\Delta \mathrm{U}}{\Delta \mathrm{t}}+\frac{\Delta \mathrm{W}}{\Delta \mathrm{t}}\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app