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JEE Mains · Physics · STD 11 - 11. thermodynamics
An electric appliance supplies \(6000\, {J} / {min}\) heat to the system. If the system delivers a power of \(90\, {W}\). How long (in \(sec\)) it would take to increase the internal energy by \(2.5 \times 10^{3}\, {J}\) ?
- A \(250\)
- B \(410\)
- C \(300\)
- D \(150\)
Answer & Solution
Correct Answer
(A) \(250\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{Q}=\Delta \mathrm{U}+\Delta \mathrm{W}\) \(\frac{\Delta \mathrm{Q}}{\Delta \mathrm{t}}=\frac{\Delta \mathrm{U}}{\Delta \mathrm{t}}+\frac{\Delta \mathrm{W}}{\Delta \mathrm{t}}\)…
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