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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

For the reaction \(2A + B \to C\),the values of initial rate at different reactant concentrations are given in the table below: The rate law for the reaction is
\([A] (mol\,L^{-1})\) \([B] (mol\,L^{-1})\) Initial Rate \((mol\, L^{-1}\,s^{-1} )\)
\(0.05\) \(0.05\) \(0.045\)
\(0.10\) \(0.05\) \(0.090\)
\(0.20\) \(0.10\) \(0.72\)
 

  1. A Rate \(= k[A]^2[B]^2\)
  2. B Rate \(= k[A][B]^2\)
  3. C Rate \(= k[A][B]\)
  4. D Rate \(= k[A]^2[B]\)
Verified Solution

Answer & Solution

Correct Answer

(B) Rate \(= k[A][B]^2\)

Step-by-step Solution

Detailed explanation

\(r\, = \,K{[A]^x}\,{[B]^y}\) \(0.045\, = \,K{(0.05)^x}{(0.05)^y}\) ...... \((1)\) \(0.090\, = \,K{(0.10)^x}{(0.05)^y}\) .......\((2)\) \(0.72\, = \,K{(0.20)^x}{(0.10)^y}\) ........\((3)\) Diving \((1)\) by \((2)\) We get…
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