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JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
\(pK_a\) of a weak acid \((HA)\) and \(pK_b\) of a weak base \((BOH)\) are \(3.2\) and \(3.4,\) respectively. The \(pH\) of their salt \((AB)\) solution is
- A \(7.2\)
- B \(6.9\)
- C \(7.0\)
- D \(1.0\)
Answer & Solution
Correct Answer
(B) \(6.9\)
Step-by-step Solution
Detailed explanation
For the salt of weak acid and weak base, we have \(\mathrm{pH} =7+\frac{1}{2} \mathrm{p} K_{\mathrm{a}}-\frac{1}{2} \mathrm{p} K_{\mathrm{b}} \) \(=7+\frac{1}{2}(3.2)-\frac{1}{2}(3.4) \) \(=6.9\)
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