JEE Mains · Physics · STD 11 - 2. motion in straight line
A body falling under gravity covers two points \(A\) and \(B\) separated by \(80 \mathrm{~m}\) in \(2 \mathrm{~s}\). The distance of upper point A from the starting point is________ \(\mathrm{m}\) (use \(\mathrm{g}=10 \mathrm{~ms}^{-2}\) )
- A \(73\)
- B \(43\)
- C \(75\)
- D \(45\)
Answer & Solution
Correct Answer
(D) \(45\)
Step-by-step Solution
Detailed explanation
From \(A \rightarrow B\) \( -80=-\mathrm{v}_1 \mathrm{t}-\frac{1}{2} \times 10 \mathrm{t}^2 \) \( -80=-2 \mathrm{v}_1-\frac{1}{2} \times 10 \times 2^2 \) \( -80=-2 \mathrm{v}_1-20 \) \( -60=-2 \mathrm{v}_1 \) \( \mathrm{v}_1=30 \mathrm{~m} / \mathrm{s}\) From \(\mathrm{O}\) to…
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