JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
Consider the following reaction at \(298 \mathrm{~K}\). \(\frac{3}{2} \mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons \mathrm{O}_{3(\mathrm{~g})} \cdot \mathrm{K}_{\mathrm{P}}=2.47 \times 10^{-29} \text {. }\) \(\Delta_{\mathrm{r}} \mathrm{G}^{\ominus}\) for the reaction is_______ \(kJ\). (Given R \(\left.=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)\)
- A \(150\)
- B \(165\)
- C \(160\)
- D \(163\)
Answer & Solution
Correct Answer
(D) \(163\)
Step-by-step Solution
Detailed explanation
\(\frac{3}{2} \mathrm{O}_{2(\mathrm{~g})} \rightleftharpoons \mathrm{O}_{3(\mathrm{~g})} \cdot \mathrm{K}_{\mathrm{P}}=2.47 \times 10^{-29}\) \(\Delta_{\mathrm{r}} \mathrm{G}^{\ominus}=-\mathrm{RT} \ln \mathrm{K}_{\mathrm{P}}\)…
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