JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
For a certain reaction at \(300 \mathrm{~K}, \mathrm{~K}=10\), then \(\Delta \mathrm{G}^{\circ}\) for the same reaction is _______ \(\times 10^{-1} \mathrm{~kJ} \mathrm{~mol}^{-1}\). (Given \(\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) )
- A \(70\)
- B \(60\)
- C \(80\)
- D \(57\)
Answer & Solution
Correct Answer
(D) \(57\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{G}^{\circ}=-\mathrm{RT}(\mathrm{n} \mathrm{K}\) \(=-8.314 \times 300 \ell \mathrm{n}(10)\) \(=5744.14 \mathrm{~J} / \mathrm{mole}\) \(=57.44 \times 10^{-1} \mathrm{~kJ} / \mathrm{mole}\)
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