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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2016, 2020, 2021
  • Medium
  • MCQ

An electron of mass \(m\) and a photon have same energy \(E.\) The ratio of de-Broglie wavelengths associated with them is

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Answer & Solution

Correct Answer

(D) \(\;\frac{1}{C}{\left( {\frac{E}{{2m}}} \right)^{\frac{1}{2}}}\)

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Detailed explanation

For electron of energy \(E\)

de-Broglie wavelength, \(\lambda_{e}=\frac{h}{p}=\frac{h}{\sqrt{2 m E}}\)

For photon of energy, \(E=h v=\frac{h c}{\lambda_{p}}\)

\({\Rightarrow \lambda_{p}=\frac{h c}{E}}\)

\({\therefore \frac{\lambda_{e}}{\lambda_{p}}=\frac{h}{\sqrt{2 m E}} \times \frac{E}{h c}=\frac{1}{c}\left(\frac{E}{2 m}\right)^{1 / 2}}\)

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