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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2016, 2020, 2021
- Medium
- MCQ
An electron of mass \(m\) and a photon have same energy \(E.\) The ratio of de-Broglie wavelengths associated with them is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\;\frac{1}{C}{\left( {\frac{E}{{2m}}} \right)^{\frac{1}{2}}}\)
Step-by-step Solution
Detailed explanation
For electron of energy \(E\)
de-Broglie wavelength, \(\lambda_{e}=\frac{h}{p}=\frac{h}{\sqrt{2 m E}}\)
For photon of energy, \(E=h v=\frac{h c}{\lambda_{p}}\)
\({\Rightarrow \lambda_{p}=\frac{h c}{E}}\)
\({\therefore \frac{\lambda_{e}}{\lambda_{p}}=\frac{h}{\sqrt{2 m E}} \times \frac{E}{h c}=\frac{1}{c}\left(\frac{E}{2 m}\right)^{1 / 2}}\)
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