JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
A commercially sold conc. \(HCl\) is \(35 \% HCl\) by mass. If the density of this commercial acid is \(1.46\) \(g / mL\), the molarity of this solution is ....\(M\) (Atomic mass : \(Cl =35.5 \,amu , H =1\, amu\) )
- A \(10.2\)
- B \(12.5\)
- C \(14.0\)
- D \(18.2\)
Answer & Solution
Correct Answer
(C) \(14.0\)
Step-by-step Solution
Detailed explanation
Let total volume \(=1000 \,mL =1 \,L\) total mass of solution \(=1460 \,g\) mass of \(HCl =\frac{35}{100} \times 1460\) moles of \(HCl =\frac{35 \times 1460}{100 \times 36.5}\) So molarity \(=\frac{35 \times 1460}{100 \times 36.5}=14 \,M\)
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