JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Consider the figure provided. \(1 \mathrm{~mol}\) of an ideal gas is kept in a cylinder, fitted with a piston, at the position \(\mathrm{A}\), at \(18^{\circ} \mathrm{C}\). If the piston is moved to position \(B\), keeping the temperature unchanged, then ' \(x\) ' \(L\) atm work is done in this reversible process. \(\mathrm{x}=\) _______ \(\mathrm{L} \mathrm{atm.} \mathrm{(nearest} \mathrm{integer)}\) [Given : Absolute temperature \(={ }^{\circ} \mathrm{C}+273.15\), \(\left.\mathrm{R}=0.08206 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right]\)

- A \(50\)
- B \(55\)
- C \(60\)
- D \(65\)
Answer & Solution
Correct Answer
(B) \(55\)
Step-by-step Solution
Detailed explanation
\(\omega=-\mathrm{nRT} \ln \left(\frac{\mathrm{V}_2}{\mathrm{~V}_1}\right)\) \(=-1 \times .08206 \times 291.15 \ln \left(\frac{100}{10}\right)\) \(=-55.0128\) Work done by system \(\approx 55 \mathrm{~atm}\) lit.
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