JEE Mains · Chemistry · STD 11 - 3. Classification of elements and periodicity in properties
The successive 5 ionisation energies of an element are \(800,2427,3658,25024\) and \(32824 \mathrm{~kJ} / \mathrm{mol}\), respectively. By using the above values predict the group in which the above element is present :
- A Group 13
- B Group 14
- C Group 2
- D Group 4
Answer & Solution
Correct Answer
(A) Group 13
Step-by-step Solution
Detailed explanation
The successive 5 ionisation energies of an element are \(800,2427,3658,25024\) and \(32824 \mathrm{~kJ} / \mathrm{mol}\), respectively.…
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