JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The threshold frequency of a metal with work function \(6.63\ \mathrm{eV}\) is:
- A \(16 \times 10^{1 \mathrm{~s}} \mathrm{~Hz}\)
- B \(16 \times 10^{12} \mathrm{~Hz}\)
- C \(1.6 \times 10^{12} \mathrm{~Hz}\)
- D \(1.6 \times 10^{15} \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(D) \(1.6 \times 10^{15} \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
\( \phi_0=h v_0 \) \( 6.63 \times 1.6 \times 10^{-19}=6.63 \times 10^{-34} v_0 \) \( v_0=\frac{1.6 \times 10^{-19}}{10^{-34}} \) \( v_0=1.6 \times 10^{15} \mathrm{~Hz}\)
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