JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
When a salt is treated with sodium hydroxide solution it gives gas \(\mathrm{X}\). On passing gas \(\mathrm{X}\) through reagent \(\mathrm{Y}\) a brown coloured precipitate is formed. \(\mathrm{X}\) and \(\mathrm{Y}\) respectively are _______.
- A \(\mathrm{X}=\mathrm{NH}_3\) and \(\mathrm{Y}=\mathrm{HgO}\)
- B \(\mathrm{X}=\mathrm{NH}_3\) and \(\mathrm{Y}=\mathrm{K}_2 \mathrm{HgI}_4+\mathrm{KOH}\)
- C \(\mathrm{X}=\mathrm{NH}_4 \mathrm{Cl}\) and \(\mathrm{Y}=\mathrm{KOH}\)
- D \(\mathrm{X}=\mathrm{HCl}\) and \(\mathrm{Y}=\mathrm{NH}_4 \mathrm{Cl}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{X}=\mathrm{NH}_3\) and \(\mathrm{Y}=\mathrm{K}_2 \mathrm{HgI}_4+\mathrm{KOH}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{NH}_4^{+}+\mathrm{NaOH} \longrightarrow \mathrm{H}_2 \mathrm{O}+\mathrm{NH}_3 \uparrow\) \(\mathrm{NH}_4^{+}+\mathrm{NaOH} \longrightarrow \mathrm{H}_2 \mathrm{O}+\mathrm{NH}_3 \uparrow\) \(\mathrm{NH}_3\) is identify by…
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