JEE Mains · Physics · STD 12 - Magnetism and matter
- JEE Mains 2021
- Medium
- MCQ
At an angle of \(30^{\circ}\) to the magnetic meridian, the apparent dip is \(45^{\circ} .\) Find the true dip :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(\tan ^{-1} \frac{\sqrt{3}}{2}\)
Step-by-step Solution
Detailed explanation
\(A \tan \delta=\tan \delta^{\prime} \cos \theta\)
\(=\tan 45^{\circ} \cos 30^{\circ}\)
\(\tan \delta=1 \times \frac{\sqrt{3}}{2}\)
\(\delta=\tan ^{-1}\left(\frac{\sqrt{3}}{2}\right)\)
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