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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

Combustion of glucose \(\left(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\right)\) produces \(\mathrm{CO}_2\) and water. The amount of oxygen (in \(\mathrm{g}\) ) required for the complete combustion of \(900 \mathrm{~g}\) of glucose is _______. [Molar mass of glucose in \(\mathrm{g} \mathrm{mol}^{-1}=180\) ]

  1. A \(480\)
  2. B \(960\)
  3. C \(800\)
  4. D \(32\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(960\)

Step-by-step Solution

Detailed explanation

Balanced equation: C6H12O6 + 6O2 → 6CO2 + 6H2O Molar mass of glucose = (6×12 + 12×1 + 6×16) = 180 g 180 g glucose requires 6×32 = 192 g O2 900 g glucose = (900/180) = 5 moles O2 required = 5×192 = 960 g
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