The Wheatstone bridge shown in Fig. here, gets balanced when the carbon resistor used as R1 has the colour code (Orange, Red, Brown). The resistors R2 and R4 are 80, and 40,, respectively. Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as R3 would be

JEE Mains · Physics · STD 12 - Current electricity

The Wheatstone bridge shown in Fig. here, gets balanced when the carbon resistor used as \(R_1\) has the colour code (Orange, Red, Brown). The resistors \(R_2\) and \(R_4\) are \(80\, \Omega \) and \(40\,\Omega \), respectively. Assuming that the colour code for the carbon resistors gives their accurate values, the colour code for the carbon resistor, used as \(R_3\) would be

Pick an option to check your answer.

Verified Solution

Correct Answer

(A) Brown, Blue, Brown

Detailed explanation

\(R_{1}=32 \times 10=320 \,\Omega\)

\(\mathrm{R}_{3}=\frac{\mathrm{R}_{\mathrm{y}}}{\mathrm{R}_{2}} \times \mathrm{R}_{1}=\frac{40 \times 320}{80}=160 \,\Omega\)

\(\therefore \) Colour code of \(\mathrm{R}_{3}\) be Brown, Blue, Brown.

Same subject

From JEE Mains