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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2023
  • Hard
  • Numerical

A block of mass \(5\,kg\) starting from rest pulled up on a smooth incline plane making an angle of \(30^{\circ}\) with horizontal with an affective acceleration of \(1\,ms ^{-2}\). The 10.Power delivered by the pulling force at \(t =10\,s\) from the start is \(.....\,W.\) \(\left[\right.\) Use \(\left.g =10\,ms ^{-2}\right]\) (calculate the nearest integer value)  

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Answer & Solution

Correct Answer

(A) \(300\)

Step-by-step Solution

Detailed explanation

\(F -5\,g \sin 30^{\circ}=5 a \Rightarrow F =5+25=30\,N\)

\(V _{10}= u + at \Rightarrow v _{10}=0+1(10)=10vm / s\)

\(P _{10}= Fv =300\,W\)

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