JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
Consider the following reaction:
\(3 \mathrm{PbCl}_2+2\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \rightarrow \)\(\mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2+6 \mathrm{NH}_4 \mathrm{Cl}\)
If \(72 \mathrm{mmol}\) of \(\mathrm{PbCl}_2\) is mixed with \(50 \mathrm{mmol}\) of\(\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4\), then amount of \(\mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2\) formed is _______ mmol. (nearest integer)
- A \(24\)
- B \(22\)
- C \(25\)
- D \(30\)
Answer & Solution
Correct Answer
(A) \(24\)
Step-by-step Solution
Detailed explanation
Limiting Reagent is \(\mathrm{PbCl}_2\) \(\mathrm{mmol}\) of \(\mathrm{Pb}_5\left(\mathrm{PO}_4\right)_2\) formed \(=\frac{\mathrm{mmol} \text { of } \mathrm{PbCl}_2 \text { reacted }}{3}\) \(=24 \mathrm{mmol}\)
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