JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
A solution of \(Fe _{2}\left( SO _{4}\right)_{3}\) is electrolyzed for \('x'\) min with a current of \(1.5\, A\) to deposit \(0.3482\, g\) of \(Fe\). The value of \(x\) is \(.......\). [nearest integer] Given : \(1 \,F =96500\, C \,mol ^{-1}\) Atomic mass of \(Fe =56\, g \,mol ^{-1}\)
- A \(10\)
- B \(20\)
- C \(25\)
- D \(35\)
Answer & Solution
Correct Answer
(B) \(20\)
Step-by-step Solution
Detailed explanation
\(Fe ^{3+}+3 e ^{-} \longrightarrow Fe\) \(3 F \longrightarrow 1\) mole \(Fe\) is deposited For \(56\, g \longrightarrow 3 \times 96500\) (required charge) For \(1 \,g \longrightarrow \frac{3 \times 96500}{56}\) (required charge) For…
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