JEE Mains · Physics · STD 12 - Atoms
- JEE Mains 2021
- Medium
- MCQ
If \(\lambda_{1}\) and \(\lambda_{2}\) are the wavelengths of the third member of Lyman and first member of the Paschen series respectively, then the value of \(\lambda_{1}: \lambda_{2}\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(7: 135\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{\lambda_{1}}= R \left[\frac{1}{1^{2}}-\frac{1}{4^{2}}\right]\)
\(\frac{1}{\lambda_{2}}= R \left[\frac{1}{3^{2}}-\frac{1}{4^{2}}\right]\)
\(\frac{\lambda_{1}}{\lambda_{2}}=\frac{\left[\frac{1}{9}-\frac{1}{16}\right]}{\left[1-\frac{1}{16}\right]}=\frac{7}{9 \times 15}\)
\(\frac{\lambda_{1}}{\lambda_{2}}=\frac{7}{135}\)
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