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JEE Mains · Physics · STD 12 - Atoms
  • JEE Mains 2021
  • Medium
  • MCQ

If \(\lambda_{1}\) and \(\lambda_{2}\) are the wavelengths of the third member of Lyman and first member of the Paschen series respectively, then the value of \(\lambda_{1}: \lambda_{2}\) is

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Answer & Solution

Correct Answer

(C) \(7: 135\)

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Detailed explanation

\(\frac{1}{\lambda_{1}}= R \left[\frac{1}{1^{2}}-\frac{1}{4^{2}}\right]\)

\(\frac{1}{\lambda_{2}}= R \left[\frac{1}{3^{2}}-\frac{1}{4^{2}}\right]\)

\(\frac{\lambda_{1}}{\lambda_{2}}=\frac{\left[\frac{1}{9}-\frac{1}{16}\right]}{\left[1-\frac{1}{16}\right]}=\frac{7}{9 \times 15}\)

\(\frac{\lambda_{1}}{\lambda_{2}}=\frac{7}{135}\)

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