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JEE Mains · Chemistry · STD 11 - 7. Redox reactions

The oxidation states of transition metal atoms in \(K _{2} Cr _{2} O _{7}, KMnO _{4}\) and \(K _{2} FeO _{4},\) respectively, are \(x , y\) and \(z\). The sum of \(x , y\) and \(z\) is

  1. A \(12\)
  2. B \(25\)
  3. C \(19\)
  4. D \(22\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(19\)

Step-by-step Solution

Detailed explanation

\(K _{2} Cr _{2} O _{7}\) \(2(+1)+2 x+7(-2)=0\) \(x=+6\) In \(K _{2} Cr _{2} O _{7},\) Transition metal \(( Cr )\) present in +6 oxidation state. \(KMnO _{4}\) \((+1)+y+4(-2)=0\) \(x=+7\) In \(KMnO _{4}\), transition metal (Mn) present in \(+7\) oxidation state…
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