JEE Mains · Physics · STD 11 - 14. waves and sound
The end correction of a resonance column is \(1\,cm.\) If the shortest length resonating with the tuning fork is \(10\,cm,\) the next resonating length should be ..... \(cm\)
- A \(32\)
- B \(40\)
- C \(28\)
- D \(36\)
Answer & Solution
Correct Answer
(A) \(32\)
Step-by-step Solution
Detailed explanation
For first resonance, \(\frac{\lambda}{4}=\ell_{1}+\mathrm{e}=11 \mathrm{cm}\) \((\because \text { end correction } \mathrm{e}=1 \mathrm{cm} \text { given })\) For second resonance, \(\frac{3 \lambda}{4}=\ell_{2}+\mathrm{e}\) \(\Rightarrow \ell_{2}=3 \times 11-1=32 \mathrm{cm}\)
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