JEE Mains · Physics · STD 11 - Waves and sound
- JEE Mains 2018
- Hard
- Numerical
The end correction of a resonance column is \(1\,cm.\) If the shortest length resonating with the tuning fork is \(10\,cm,\) the next resonating length should be ..... \(cm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(32\)
Step-by-step Solution
Detailed explanation
For first resonance, \(\frac{\lambda}{4}=\ell_{1}+\mathrm{e}=11 \mathrm{cm}\)
\((\because \text { end correction } \mathrm{e}=1 \mathrm{cm} \text { given })\)
For second resonance, \(\frac{3 \lambda}{4}=\ell_{2}+\mathrm{e}\)
\(\Rightarrow \ell_{2}=3 \times 11-1=32 \mathrm{cm}\)
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