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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2018
  • Hard
  • Numerical

The end correction of a resonance column is \(1\,cm.\)  If the shortest length resonating with the tuning fork is \(10\,cm,\)  the next resonating length should be ..... \(cm\)

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Answer & Solution

Correct Answer

(A) \(32\)

Step-by-step Solution

Detailed explanation

For first resonance, \(\frac{\lambda}{4}=\ell_{1}+\mathrm{e}=11 \mathrm{cm}\)

\((\because \text { end correction } \mathrm{e}=1 \mathrm{cm} \text { given })\)

For second resonance, \(\frac{3 \lambda}{4}=\ell_{2}+\mathrm{e}\)

\(\Rightarrow \ell_{2}=3 \times 11-1=32 \mathrm{cm}\)

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