JEE Mains · Chemistry · STD 11 - 2. structure of atom
The de-Broglie wavelength of a particle of mass \(6.63\,g\) moving with a velocity of \(100\,ms^{-1}\) is
- A \(10^{-33}\,m\)
- B \(10^{-35}\,m\)
- C \(10^{-31}\,m\)
- D \(10^{-25}\,m\)
Answer & Solution
Correct Answer
(A) \(10^{-33}\,m\)
Step-by-step Solution
Detailed explanation
De Broglie wavelength \(\left( \lambda \right) = \frac{h}{{mv}}\) \(\frac{{6.63 \times {{10}^{ - 34}}}}{{6.63 \times {{10}^{ - 3}} \times 100}} = {10^{ - 33}}\,m\)
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