JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A body of weight \(200 \mathrm{~N}\) is suspended form a tree branch thought a chain of mass \(10 \mathrm{~kg}\). The branch pulls the chain by a force equal to _______. (if \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(150 \mathrm{~N}\)
- B \(300 \mathrm{~N}\)
- C \(200 \mathrm{~N}\)
- D \(100 \mathrm{~N}\)
Answer & Solution
Correct Answer
(B) \(300 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Chain block system is in equilibrium so \(\mathrm{T}=200+100=300 \mathrm{~N} \text {. }\)
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