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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance

दो बिन्दु आवेश \(4 q\) व \(- q ; x-\)अक्ष पर क्रमशः \(x =-\frac{ d }{2}\) व \(x\) \(=\frac{ d }{2}\) पर स्थिर है। यदि एक तीसरे बिन्दु आवेश \('q'\) को मूलबिन्दु से \(x = d\) तक अर्धवृत्त के अनुदिश चित्रानुसार ले जाया जाये तो आवेश की ऊर्जा ।

  1. A \(\frac{2 q ^{2}}{3 \pi \varepsilon_{0} d }\) गुना बढ़ जायेगी।
  2. B \(\frac{3 q ^{2}}{4 \pi \varepsilon_{0} d }\) गुना बढ़ जायेगी।
  3. C \(\frac{4 q ^{2}}{3 \pi \varepsilon_{0} d }\) गुना घट जायेगी।
  4. D \(\frac{ q ^{2}}{4 \pi \varepsilon_{0} d }\) गुना घट जायेगी।
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{4 q ^{2}}{3 \pi \varepsilon_{0} d }\) गुना घट जायेगी।

Step-by-step Solution

Detailed explanation

Potential of \(- q\) is same as initial and final point of the path therefore potential due to \(4 q\) will only change and as potential is decreasing the energy will decrease Decrease in potential energy \(=q\left( V _{ i }- V _{ f }\right)\) Decrease in potential energy…
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