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JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion

\(50\, g , 100 \,g\) तथा \(150 \,g\) के तीन कणों को चित्रानुसार \(1\, m\) भुजा वाले एक समबाहु त्रिभुज के कोनों पर रखा है। इस निकाय के द्रव्यमान केन्द्र ( \(x\) तथा \(y\) ) के निर्देशांक होंगे।

  1. A \(\left( {\frac{{\sqrt 3 }}{7}\,m,\,\frac{7}{{12}}\,m} \right)\)
  2. B \(\left( {\frac{7}{{12}}m,\,\frac{{\sqrt 3 }}{8}\,m} \right)\)
  3. C \(\left( {\frac{{\sqrt 3 }}{4}\,m,\,\frac{5}{{12}}\,m} \right)\)
  4. D \(\left( {\frac{7}{{12}}m,\,\frac{{\sqrt 3 }}{4}\,m} \right)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\left( {\frac{7}{{12}}m,\,\frac{{\sqrt 3 }}{4}\,m} \right)\)

Step-by-step Solution

Detailed explanation

The co-ordinates of the center of mass \({\overrightarrow r _{cm}} = \frac{{0 + 150 \times \left( {\frac{1}{2}i + \frac{{\sqrt 3 }}{2}\hat j} \right) + 100 \times \hat i}}{{300}}\) \({\overrightarrow r _{cm}} = \frac{7}{{12}}\hat i + \frac{{\sqrt 3 }}{4}\hat j\)…
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