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JEE Mains · Maths · STD 12 - 2. inverse trigonometric function

यदि \(k=tan(\frac{\pi}{4}+\frac{1}{2}cos^{-1}(\frac{2}{3}))+tan(\frac{1}{2}sin^{-1}(\frac{2}{3}))\) है, तो समीकरण \(sin^{-1}(kx-1)=sin^{-1}x-cos^{-1}x\) के हलों की संख्या ___ है।

  1. A 1
  2. B 2
  3. C 0
  4. D 3
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Correct Answer

(A) 1

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Detailed explanation

Let \(\theta=\frac{1}{2} \sin ^{-1} \frac{2}{3}\), then \(\frac{1}{2} \cos ^{-1} \frac{1}{3}=\left(\frac{\pi}{4}-\theta\right)\) \(\mathrm{k}=\tan \theta+\cot \theta=\frac{1}{\sin \theta \cos \theta}=\frac{2}{\sin 2 \theta}\) \(\mathrm{k}=\frac{2}{\frac{2}{3}}=3\)…
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