JEE Mains · Maths · STD 12 - 2. inverse trigonometric function
If \(k=tan(\frac{\pi}{4}+\frac{1}{2}cos^{-1}(\frac{2}{3}))+tan(\frac{1}{2}sin^{-1}(\frac{2}{3}))\) then the number of solutions of the equation \(sin^{-1}(kx-1)=sin^{-1}x-cos^{-1}x\) is ___ .
- A 1
- B 2
- C 0
- D 3
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Let \(\theta=\frac{1}{2} \sin ^{-1} \frac{2}{3}\), then \(\frac{1}{2} \cos ^{-1} \frac{1}{3}=\left(\frac{\pi}{4}-\theta\right)\) \(\mathrm{k}=\tan \theta+\cot \theta=\frac{1}{\sin \theta \cos \theta}=\frac{2}{\sin 2 \theta}\) \(\mathrm{k}=\frac{2}{\frac{2}{3}}=3\)…
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