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JEE Mains · Maths · STD 12 - 11. three dimension geometry

माना समतल \(\mathrm{P}\) समतलों \(2 \mathrm{x}+3 \mathrm{y}-\mathrm{z}=2\) तथा \(\mathrm{x}+2 \mathrm{y}+3 \mathrm{z}=6\) के प्रतिछेदन से होकर जाता है तथा समतल \(2 \mathrm{x}+\mathrm{y}-\mathrm{z}+1=0\) के लंबवत है। यदि \(\mathrm{P}\) की बिन्दु \((-7,1,1)\) से दूरी \(\mathrm{d}\) है, \(\mathrm{d}^2\) बराबर है:

  1. A \(\frac{250}{83}\)
  2. B \(\frac{15}{53}\)
  3. C \(\frac{25}{83}\)
  4. D \(\frac{250}{82}\)
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Answer & Solution

Correct Answer

(A) \(\frac{250}{83}\)

Step-by-step Solution

Detailed explanation

\(P \equiv P _1+\lambda P _2=0\) \((2+\lambda) x +(3+2 \lambda) y+(3 \lambda-1) z-2-6 \lambda=0\) Plane \(P\) is perpendicular to \(P_3 \therefore \vec{n} \cdot \vec{n}_3=0\) \(2(\lambda+2)+(2 \lambda+3)-(3 \lambda-1)=0\) \(\lambda=-8\) \(P \equiv-6 x-13 y-25 z+46=0\)…
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