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JEE Mains · Maths · STD 12 - 7.2 definite integral

\(\alpha\) का एक मान, जिसके लिये \(\int \limits_{\alpha}^{\alpha+1} \frac{d x}{(x+\alpha)(x+\alpha+1)}=\log _{ e }\left(\frac{9}{8}\right)\) है

  1. A \(-\frac{1}{2}\)
  2. B \(-2\)
  3. C \(\frac{1}{2}\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-2\)

Step-by-step Solution

Detailed explanation

\(\int_{\alpha}^{\alpha+1} \frac{d x}{(x+\alpha)(x+\alpha+1)}=\log _{e}\left(\frac{9}{8}\right)\) \(\Rightarrow \int_{\alpha}^{\alpha+1} \frac{(x+\alpha+1)-(x+\alpha)}{(x+\alpha)(x+\alpha+1)} d x=\log _{e}\left(\frac{9}{8}\right)\)…
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