સમક્ષિતિજ સાથે \(15^{\circ}\) ના ખૂણે પ્રક્ષેપન કરેલા પ્રક્ષિપ્ત પદાર્થની અવધિ \(50\,m\) છે.જો આ પદાર્થનું સમક્ષિતિજ સાથે \(45^{\circ}\) ના ખૂણે આટલા જ વેગથી પ્રક્ષેપન કરવામાં આવે તો તેની અવધિ \(........\,m\) થશે.

A \(50\)
B \(50 \sqrt{2}\)
C \(100\)
D \(100 \sqrt{2}\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(100\)

Step-by-step Solution

Detailed explanation

\(R =\frac{ v ^2 \sin 2 \theta}{ g }\) \(R \propto \sin (2 \theta)\) \(\frac{ R _1}{ R _2}=\frac{\sin \left(2 \theta_1\right)}{\sin \left(2 \theta_2\right)}=\frac{\sin (2 \times 15)}{\sin (2 \times 45)}=\frac{\sin 30^{\circ}}{\sin 90^{\circ}}\) \(\frac{50}{ R _2}=\frac{1}{2}\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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