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JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2023
  • Medium
  • Numerical

The range of the projectile projected at an angle of \(15^{\circ}\) with horizontal is \(50\,m\). If the projectile is projected with same velocity at an angle of \(45^{\circ}\) with horizontal, then its range will be \(........\,m\)

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Answer & Solution

Correct Answer

(C) \(100\)

Step-by-step Solution

Detailed explanation

\(R =\frac{ v ^2 \sin 2 \theta}{ g }\)

\(R \propto \sin (2 \theta)\)

\(\frac{ R _1}{ R _2}=\frac{\sin \left(2 \theta_1\right)}{\sin \left(2 \theta_2\right)}=\frac{\sin (2 \times 15)}{\sin (2 \times 45)}=\frac{\sin 30^{\circ}}{\sin 90^{\circ}}\)

\(\frac{50}{ R _2}=\frac{1}{2}\)

\(R _2=100\,m\)

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