JEE Mains · Physics · STD 11 - Motion in plane
- JEE Mains 2023
- Medium
- Numerical
The range of the projectile projected at an angle of \(15^{\circ}\) with horizontal is \(50\,m\). If the projectile is projected with same velocity at an angle of \(45^{\circ}\) with horizontal, then its range will be \(........\,m\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(100\)
Step-by-step Solution
Detailed explanation
\(R =\frac{ v ^2 \sin 2 \theta}{ g }\)
\(R \propto \sin (2 \theta)\)
\(\frac{ R _1}{ R _2}=\frac{\sin \left(2 \theta_1\right)}{\sin \left(2 \theta_2\right)}=\frac{\sin (2 \times 15)}{\sin (2 \times 45)}=\frac{\sin 30^{\circ}}{\sin 90^{\circ}}\)
\(\frac{50}{ R _2}=\frac{1}{2}\)
\(R _2=100\,m\)
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