સાદા લોલક દ્વારા ગુરુત્વપ્રવેગ \(g\) શોધવાના પ્રયોગ માટે લોલકનાં આવર્તકાળના વર્ગ વિરુદ્ધ લંબાઇનો ગ્રાફ આપેલ છે તો આ જગ્યા પાસે ગુરુત્વપ્રવેગ \(g\) નું \(m/s^2\) ના સ્વરૂપમાં મૂલ્ય કેટલું હશે?

A \(9.81\)
B \(9.87\)
C \(9.91\)
D \(10\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(9.87\)

Step-by-step Solution

Detailed explanation

From graph it is clear that wher \(\mathrm{L}=1 \mathrm{m}, \mathrm{T}^{2}=4 \mathrm{s}^{2}\) As we know, \(\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}\) \(\Rightarrow \mathrm{g}=\frac{4 \pi^{2} \mathrm{L}}{\mathrm{T}^{2}}\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From JEE Mains

Explore more questions on app