\(M\) દળ અને \(R\) ત્રિજ્યા ધરાવતા ગોળમાંથી \(\frac{R}{2}\) ત્રિજ્યા ધરાવતો ગોળો કાપીને આકૃતિમાં દર્શાવ્યા પ્રમાણે મૂકેલા છે.જેમાં બંને ગોળાના કેન્દ્ર વચ્ચેનું અંતર \(3R\) છે.તો બંને ગોળા વચ્ચે લાગતું ગુરુત્વાકર્ષણ બળ કેટલું હશે?

A \(\frac{{41G{M^2}}}{{3600{R^2}}}\)
B \(\frac{{41G{M^2}}}{{450{R^2}}}\)
C \(\frac{{59G{M^2}}}{{450{R^2}}}\)
D \(\frac{{G{M^2}}}{{225{R^2}}}\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{{41G{M^2}}}{{3600{R^2}}}\)

Step-by-step Solution

Detailed explanation

Volume of removed sphere \({V_{remo}} = \frac{4}{3}\pi {\left( {\frac{R}{2}} \right)^3} = \frac{4}{3}\pi {R^3}\left( {\frac{1}{8}} \right)\) Volume of the sphere (remaining) \({V_{remain}} = \frac{4}{3}\pi {R^3} - \frac{4}{3}\pi {R^3}\left( {\frac{1}{8}} \right)\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From JEE Mains

Explore more questions on app