\(\frac{\text { ' } a \text { ' }}{2}\) લંબાઈનો એક રેખીય વિદ્યુતભાર, ' \(a\) ' ધારની લંબાઈ ધરાવતા સમઘન \(A B C D E F G H\) ની ધાર \(B C\) ના કેન્દ્ર પર આકૃતિમાં દર્શાવ્યા મુજબ રાખેલ છે. જો રેખીય વિદ્યુતભારની ઘનતા પ્રતિ એકમ લંબાઈ દીઠ \(\lambda\) C હોય, તો સમઘનની તમામ સપાટીઓમાંથી પસાર થતું કુલ વિદ્યુત ફ્લક્સ _______ હશે. (અહીં \(\epsilon_0\) ને શૂન્યાવકાશની પરમિટિવિટી લો)

A \(\frac{\lambda \mathrm{a}}{2 \epsilon_0}\)
B \(\frac{\lambda \mathrm{a}}{4 \epsilon_0}\)
C \(\frac{\lambda \mathrm{a}}{16 \epsilon_0}\)
D \(\frac{\lambda \mathrm{a}}{8 \epsilon_0}\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\lambda \mathrm{a}}{8 \epsilon_0}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { Charge of the line charge }=\frac{a \lambda}{2} \\ & \text { Portion of wire inside cube }=\frac{1}{4} \\ & \therefore \quad q_{e n}=\frac{1}{4}\left(\frac{a \lambda}{2}\right)=\frac{a \lambda}{8} \\ & \qquad \phi=\frac{q_{e n}}{\varepsilon_0}=\frac{a…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From JEE Mains

Explore more questions on app