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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance

\(10^{-6} \mu \mathrm{C}\) નો એક વીજભાર \(X-Y\) યામ પધ્ધતિના ઉગમબિંદુ \((0,0) \mathrm{m}\) પર મૂકેલો છે. બિંદુઓ \(\mathrm{P}\) અને \(\mathrm{Q}\) અનુક્રમે \((\sqrt{3}, \sqrt{3}) \mathrm{m}\) અને \((\sqrt{6}, 0) \mathrm{m}\) પર રહેલા છે. બિંદુઓ\(\mathrm{P}\) અને \(\mathrm{Q}\) વચચેનો સ્થિતિમાન તફાવત_____થશે.

  1. A  \(\sqrt{3} \mathrm{~V}\)
  2. B  \(\sqrt{6} \mathrm{~V}\)
  3. C  \(0 \mathrm{~V}\)
  4. D \(3 \mathrm{~V}\)
Verified Solution

Answer & Solution

Correct Answer

(C)  \(0 \mathrm{~V}\)

Step-by-step Solution

Detailed explanation

Potential difference \(=\frac{K Q}{r_1}-\frac{K Q}{r_2}\) \( \mathrm{r}_1=\sqrt{(\sqrt{3})^2+(\sqrt{3})^2}\) \( \mathrm{r}_2=\sqrt{(\sqrt{6})^2+0}\) As \(r_1=r_2=\sqrt{6} \mathrm{~m}\) So potential difference \(=0\)
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