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JEE Mains · Maths · STD 12 - 11. three dimension geometry

રેખાઓ \(\frac{x-2}{3}=\frac{y+1}{2}=\frac{z-6}{2}\) અને \(\frac{x-6}{3}=\frac{1-y}{2}=\frac{z+8}{0}\) વચ્ચેનું ન્યુનતમ અંતર \(............\) છે.

  1. A \(13\)
  2. B \(12\)
  3. C \(14\)
  4. D \(16\)
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Answer & Solution

Correct Answer

(C) \(14\)

Step-by-step Solution

Detailed explanation

Shortest distance between the lines…
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