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JEE Mains · Maths · STD 12 - 11. three dimension geometry

અહી \(L\) એ સમતલો \(\vec{r} \cdot(\hat{\mathrm{i}}-\hat{\mathrm{j}}+2 \hat{\mathrm{k}})=2\) અને \(\vec{r} \cdot(2 \hat{\mathrm{i}}+\hat{\mathrm{j}}-\hat{\mathrm{k}})=2\) ની છેદરેખા છે. જો બિંદુ \((1,2,0)\) માંથી રેખા \(L\) પરનો લંબપાદ \(\mathrm{P}(\alpha, \beta, \gamma)\) હોય તો  \(35(\alpha+\beta+\gamma)\) ની કિમંત મેળવો.

  1. A \(134\)
  2. B \(119\)
  3. C \(143\)
  4. D \(101\)
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Answer & Solution

Correct Answer

(B) \(119\)

Step-by-step Solution

Detailed explanation

\(P_{1}: x-y+2 z=2\) \(P_{2}=2 x+y-3=2\) Let line of Intersection of planes \(P_{1}\) and \(P_{2}\) cuts \(x y\) plane in point \(Q\). \(\Rightarrow \quad z\)-coordinate of point \(Q\) is zero \(\Rightarrow x-y=2\) and \(2 x+y=2\} \Rightarrow x=\frac{4}{3}, y=\frac{-2}{3}\)…
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