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JEE Mains · Maths · STD 12 - 10. vector algebra

અહી \(\vec{a}\) અને  \(\vec{b}\) બે સદીશ આપેલ છે કે જેથી \(|\vec{a}+\vec{b}|^{2}=|\vec{a}|^{2}+2|\vec{b}|^{2}, \vec{a} \cdot \vec{b}=3 \) અને \(|\vec{a} \times \vec{b}|^{2}=75\) હોય તો  \(|\vec{a}|^{2}\) ની કિમંત \(.......\) થાય.

  1. A \(14\)
  2. B \(13\)
  3. C \(12\)
  4. D \(11\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(14\)

Step-by-step Solution

Detailed explanation

\(|\vec{a}+\vec{b}|^{2}=|\vec{a}|^{2}+2|\vec{b}|^{2} ; \vec{a} \cdot \vec{b}=3\) As \(|\vec{a}|^{2}+|\vec{b}|^{2}+2 \vec{a} \cdot \vec{b}=|\vec{a}|^{2}+2|\vec{b}|^{2}\) \(|\vec{b}|^{2}=2 \vec{a} \cdot \vec{b}=6\) \(|\vec{a} \times \vec{b}|^{2}=75\)…
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