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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

જો \(x^2 + y^2 + sin\, y = 4\), હોય તો  \(\frac{{{d^2}y}}{{d{x^2}}}\) ની કિમંત  બિંદુ \((- 2, 0)\) આગળ મેળવો.

  1. A \(-34\)
  2. B \(-32\)
  3. C \(-2\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-34\)

Step-by-step Solution

Detailed explanation

Given, \({x^2} + {y^2} + \sin y = 4\) After differentiating the above equation w.r.t.\(x\) we get \(2x + 2y + \frac{{dy}}{{dx}} + \cos y\frac{{dy}}{{dx}} = 0\,......\left( 1 \right)\) \( \Rightarrow 2x + \left( {2y + \cos y} \right)\frac{{dy}}{{dx}} = 0\)…
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