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JEE Mains · Maths · STD 12 - 11. three dimension geometry

ધારોકે રેખા \(L\) એ બિંદુ \(P(2,3,1)\) માંથી પસાર થાય છે અને રેખા \(x+3 y-2 z-2=0=x-y+2 z\) ને સમાંતર છે. જો \(L\) નું બિંદુ \((5,3,8)\) થી અંતર \(x+3 y-2 z-2=0=x-y+2 z\) હોય, તો \(3 \alpha^2=..........\)

  1. A \(157\)
  2. B \(158\)
  3. C \(159\)
  4. D \(156\)
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Answer & Solution

Correct Answer

(B) \(158\)

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Detailed explanation

\(\left|\begin{array}{ccc}\hat{ i } & \hat{ j } & \hat{ k } \\ 1 & 3 & -2 \\ 1 & -1 & 2\end{array}\right|=4 \hat{ i }-4 \hat{ j }-4 \hat{ k }\) \(\therefore\) Equation of line is \(\frac{ x -2}{1}=\frac{ y -3}{-1}=\frac{ z -1}{-1}\) Let \(Q\) be \((5,3,8)\) and foot of \(\perp\)…
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