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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

જો \(x = \sqrt {{2^{\cos e{c^{ - 1}}t}}} \)  અને  \(y = \sqrt {{2^{se{c^{ - 1}}t}}} (\left| t \right|\,\, \ge \,1\,),\)  તો \(\frac{{dy}}{{dx}}\)  ની કિમંત મેળવો.

  1. A \(\frac {y}{x}\)
  2. B \(-\frac {y}{x}\)
  3. C \(-\frac {x}{y}\)
  4. D \(\frac {x}{y}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-\frac {y}{x}\)

Step-by-step Solution

Detailed explanation

Here, \(\frac{{dx}}{{dt}} = \frac{1}{{2\sqrt {{2^{\cos e{c^{ - {1_t}}}}}} }}{2^{\cos e{c^{ - {1_t}}}}}\log 2.\frac{{ - 1}}{{x\sqrt {{x^2}} - 1}}\) \(\frac{{dy}}{{dt}} = \frac{1}{{2\sqrt {{2^{se{c^{ - {1_t}}}}}} }}{2^{se{c^{ - {1_t}}}}}\log 2.\frac{{ - 1}}{{x\sqrt {{x^2}} - 1}}\)…
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