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JEE Mains · Maths · STD 12 - 1. relation and function

જો \(f\left( n \right) = \left[ {\frac{1}{3} + \frac{{3n}}{{100}}} \right]n\) , જ્યાં \([n]\) મહત્તમ પૂર્ણાંક વિધેય હોય તો \(\sum\limits_{n = 1}^{56} {f\left( n \right)} \) ની કિમત મેળવો. 

  1. A \(56\)
  2. B \(689\)
  3. C \(1287\)
  4. D \(1399\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1399\)

Step-by-step Solution

Detailed explanation

Let \(f\left( n \right) = \left[ {\frac{1}{3} + \frac{{3n}}{{100}}} \right]n\) where \(\left[ n \right]\) is greatest integer functon, \( = \left[ {0.33 + \frac{{3n}}{{100}}} \right]n\) For \(n = 1,2,....,22,\) we get \(f\left( n \right) = 0\) and for \(n = 23,24,....,55,\) we…
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