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JEE Mains · Maths · STD 12 - 11. three dimension geometry

રેખા \(2(x + 1)\,= y\, = z + 4\)  અને સમતલ  \(2x -\sqrt \lambda  \,z+4\,=0\) વચ્ચેનો ખૂણો  \(\frac{\pi}{6}\) હોય તો  \(\lambda \) મેળવો.

  1. A \(\frac{135}{7}\)
  2. B \(\frac{45}{11}\)
  3. C \(\frac{45}{7}\)
  4. D \(\frac{135}{11}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{45}{7}\)

Step-by-step Solution

Detailed explanation

Given equation of line can be written as \(\frac{x+1}{1}=\frac{y}{2}=\frac{z+4}{2}\) Eqn of plane is \(2 x-y+\sqrt{\lambda} z+4=0\) Since, angle between the line and the plane is \(\frac{\pi}{6}\) therefore…
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