જો વર્તુળ \(x^{2}+y^{2}=25\) નો બિંદુ \(R (3,4)\) આગળનો સ્પર્શકએ \(x\) -અક્ષ અને \(y\) -અક્ષને અનુક્રમે બિંદુ \(P\) અને \(Q\) આગળ છેદે છે અને જો \(r\) એ ઉગમબિંદુ કેન્દ્ર અને જેનું કેન્દ્ર ત્રિકોણ \(OPQ\) નું અંત:કેન્દ્ર હોય તેવા વર્તુળની ત્રિજ્યા છે તો \(r ^{2}\) મેળવો.

A \(\frac{529}{64}\)
B \(\frac{125}{72}\)
C \(\frac{625}{72}\)
D \(\frac{585}{66}\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{625}{72}\)

Step-by-step Solution

Detailed explanation

Tangent to circle \(3 x+4 y=25\) \(OP + OQ + OR =25\) In centre \(=\left(\frac{\frac{25}{4} \times \frac{25}{3}}{25}, \frac{\frac{25}{4} \times \frac{25}{3}}{25}\right)\) \(=\left(\frac{25}{12}, \frac{25}{12}\right)\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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x	0	1	2	3	4	5	6	7
p(x)	0	2k	k	3k	\(2 k ^2\)	2k	\(k ^2+ k\)	\(7 k ^2\)