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JEE Mains · Maths · STD 12 - 11. three dimension geometry

ધારોકે બિંદુઓ \((4,5,8)\) અને \((1,-7,5)\) માંથી પસાર થતી રેખા પર, બિંદુ \(P (1,-2,3)\) પરથી મળતો લંબપાદ \(N\) છે.તો \(N\) નું સમતલ \(2 x-2 y+z+5=0\) થી અંતર \(.........\) છે.

  1. A \(6\)
  2. B \(9\)
  3. C \(7\)
  4. D \(8\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(7\)

Step-by-step Solution

Detailed explanation

Equation of line \(\frac{x-4}{4-1}=\frac{y-5}{5-(-7)}=\frac{z-8}{8-5}\) \(\frac{x-4}{3}=\frac{y-5}{12}=\frac{z-8}{3}\) Let point \(N (3 \lambda+4,12 \lambda+5,3 \lambda+8)\) \(\overline{ PN }=(3 \lambda+4-1) \hat{i}+(12 \lambda+5-(-2)) \hat{ j }+(3 \lambda+8-3) \hat{ k }\)…
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