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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

જો વિધેય \(f(x) = 2x^3 + ax^2 + bx\) એ અંતરાલ \([-1, 1 ]\) પર બિંદુ \(c = \frac{1}{2}\) આગળ રોલના પ્રમેયનું પાલન કરતું હોય \(2a + b\) ની કિમંત મેળવો.

  1. A \(1\)
  2. B \(-1\)
  3. C \(2\)
  4. D \(-2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-1\)

Step-by-step Solution

Detailed explanation

\(f\left( x \right) = 2{x^3} + a{x^2} + bx\) let, \(a=-1,b=1\) Given that \(f\left( x \right)\) satisfy Roll theorem in interval \([-1,1]\) \(f\left( x \right)\) must satify two conditions. \((1)f(a)=f(b)\) \((2)f'(c)=0\) (\(c\) should be between \(a\) and \(b\) )…
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