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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

જો વિધેય \(f\) એ \(\left( {\frac{\pi }{6},\frac{\pi }{3}} \right)\) પર વ્યાખ્યાયિત છે કે જેથી \(f\,(x)\, = \,\left\{ {\begin{array}{*{20}{c}}
{\frac{{\sqrt 2 \,\cos \,x - \,1}}{{\cot \,x\, - \,1}}\,,\,x\, \ne \,\frac{\pi }{4}}\\
{k,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\, = \frac{\pi }{4}}
\end{array}} \right.\) એ સતત વિધેય હોય તો  \(k\) મેળવો.

  1. A \(1\)
  2. B \(2\)
  3. C \(\frac {1}{2}\)
  4. D \(\frac {1}{\sqrt 2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac {1}{2}\)

Step-by-step Solution

Detailed explanation

\(\therefore \,\) function should be continuous at \(x = \frac{\pi }{4}\) \(\therefore \mathop {\lim }\limits_{x \to \frac{\pi }{4}} f\left( x \right) = f\left( {\frac{\pi }{4}} \right)\)…
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